1.3=t+-4.9t^2

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Solution for 1.3=t+-4.9t^2 equation: 



1.3=t+-4.9t^2

We move all terms to the left:

1.3-(t+-4.9t^2)=0

We use the square of the difference formula

-(t-4.9t^2)+1.3=0

We get rid of parentheses

4.9t^2-t+1.3=0

We add all the numbers together, and all the variables

4.9t^2-1t+1.3=0

a = 4.9; b = -1; c = +1.3;
Δ = b2-4ac
Δ = -12-4·4.9·1.3
Δ = -24.48
Delta is less than zero, so there is no solution for the equation

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